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docs: 递归 上台阶算法
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base/function/recursion/main.go
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35
base/function/recursion/main.go
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@ -0,0 +1,35 @@
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package main
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import "fmt"
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// 递归
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// 计算 n 的阶乘 n!
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// 3! = 3 * 2 * 1
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// 4! = 4 * 3 * 2 * 1
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// 5! = 5 * 4 * 3 * 2 * 1
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func factorial(n int) int {
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if n > 0 {
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return n * factorial(n-1)
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}
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return 1
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}
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// 上台阶
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// n个台阶 一次走 1 或 2 步, 共 多少种走法
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func computed(n uint64) uint64 {
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if n == 1 {
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return 1
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}
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if n == 2 {
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return 2
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}
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return computed(n-1) + computed(n-2)
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}
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func main() {
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n := 5
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fmt.Printf("%d 的阶乘为 : %d\n", n, factorial(n))
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n = 4
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fmt.Printf("%d 个台阶 共有 : %d种走法\n", n, computed(uint64(n)))
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}
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@ -48,5 +48,4 @@ func main() {
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mf3(f4(2, 2))
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fmt.Printf("f4: %T\n", f4)
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}
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